document.write( "Question 1190731: Mr. Schwartz builds toy cars. He begins the week with a supply of 85 wheels, and uses 4 wheels for each car he builds. Mr. Schwartz plans to order more wheels once he has fewer than 40 wheels left.\r
\n" ); document.write( "\n" ); document.write( "The inequality that can be used to find the number of cars, x, Mr. Schwartz builds before he places an order for more wheels is
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Algebra.Com's Answer #822436 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "x = number of cars
\n" ); document.write( "4x = number of wheels used on x number of cars\r
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\n" ); document.write( "\n" ); document.write( "For instance, if x = 3 cars are built then he needs 4x = 4*3 = 12 wheels.\r
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\n" ); document.write( "\n" ); document.write( "He starts off with 85 wheels. Building x cars needs 4x wheels, so he'll have 85-4x wheels left over.\r
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\n" ); document.write( "\n" ); document.write( "This leftover amount must be 40 or larger (or else he'll place an order to get more wheels).\r
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\n" ); document.write( "\n" ); document.write( "Therefore, we form the inequality \"85-4x+%3E=+40\" which is the final answer.
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