document.write( "Question 1190691: April took out a $10000 loan to buy a car. The loan has an interest rate of 2.1% for 4 years with monthly payments. What will April's monthly payments be? (Round up to the cents place.)\r
\n" ); document.write( "\n" ); document.write( "With one year left on the loan, what is April's remaining balance? (Round up to the cents place.)
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Algebra.Com's Answer #822398 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "L = 10,000 = loan amount
\n" ); document.write( "i = interest rate per month = 0.021/12 = 0.00175
\n" ); document.write( "n = number of months = 12*4 = 48\r
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\n" ); document.write( "\n" ); document.write( "P = monthly payment
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "P = (10,000*0.00175)/( 1-(1+0.00175)^(-48) )
\n" ); document.write( "P = 217.387950449613
\n" ); document.write( "P = 217.39\r
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\n" ); document.write( "\n" ); document.write( "m = number of months left = 12
\n" ); document.write( "B = remaining balance with m months left
\n" ); document.write( "B = P*(1-(1+i)^(-m))/i
\n" ); document.write( "B = 217.387950449613*(1-(1+0.00175)^(-12))/(0.00175)
\n" ); document.write( "B = 2579.22270192667
\n" ); document.write( "B = 2579.22\r
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\n" ); document.write( "\n" ); document.write( "The monthly payment and remaining balance can be confirmed when using a calculator such as this one
\n" ); document.write( "https://www.calculator.net/loan-calculator.html
\n" ); document.write( "After you type in the proper values, and hit \"calculate\", it should show the monthly payment being $217.39
\n" ); document.write( "Also, click on \"View Amortization Table\". Note the balance at the end of month 36 (and at the beginning of month 37) is exactly $2,579.22\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "monthly payment = $217.39
\n" ); document.write( "Remaining balance with one year left = $2,579.22
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