document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112868>Question 112868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem says to:<BR>\n" );
document.write( "Solve the system of linear equations.<BR>\n" );
document.write( "-3x-6y=5<BR>\n" );
document.write( "4x+8y=5\r<BR>\n" );
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document.write( "I think that my teacher wants me to use the multiplication method. Like when you multiply one of the equations by something so that the y's or x's are exact opposites so they can add together and be solved. I just can't figure out what to add, nothing seems to work evenly. <BR>\n" );
document.write( "<3 Alyssa<BR>\n" );
document.write( "Thanx for taking the time to read this!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82233 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you're right about the solution technique<BR>\n" );
document.write( "___ but in this case it is easier to multiply both equations to get the right numbers\r<BR>\n" );
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document.write( "first equation by 4 gives -12x-24y=20\r<BR>\n" );
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document.write( "second equation by 3 gives 12x+24y=15\r<BR>\n" );
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document.write( "adding the two new equations gives 0=35; since this is not true, the equations are inconsistent<BR>\n" );
document.write( "___ there is no solution\r<BR>\n" );
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document.write( "if the original equations were graphed; they would be parallel lines </SPAN>\n" );
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