document.write( "Question 1190564: Hello, Good evening, I need help on my homework. I am having a hard time doing Random Sampling\r
\n" ); document.write( "\n" ); document.write( "A population consists of (3,8,10,15). Consider all possible sample size 2 that can be drawn with replacement.\r
\n" ); document.write( "\n" ); document.write( "-what is the standard deviation of the sampling distribution of means? = \r
\n" ); document.write( "\n" ); document.write( "-what is the population mean? =\r
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\n" ); document.write( "\n" ); document.write( "-what is the population variance? = \r
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\n" ); document.write( "\n" ); document.write( "A population consists of (3,8,10,15). Consider all possible sample size
\n" ); document.write( " 2 that can be drawn without replacement.\r
\n" ); document.write( "\n" ); document.write( "-what is the variance of the sampling distribution of means? =\r
\n" ); document.write( "\n" ); document.write( "-what is the standard deviation of the sampling distribution of means? = \r
\n" ); document.write( "\n" ); document.write( "-what is the mean of the sampling distribution of means? = \r
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Algebra.Com's Answer #822328 by chitrank(4)\"\" \"About 
You can put this solution on YOUR website!
Let the first sample be denoted by random variable \"X_1\" and the second sample by \"X_2\".
\n" ); document.write( "First few notes about \"X_1\"and \"X_2\".
\n" ); document.write( "---1 They are indepdent RVs. Why? Because sampling happens with replacement. Which means, if I sample \"X_1\", then no matter what\"X_1\" really was, the distribution of \"X_2\" remains the same.\r
\n" ); document.write( "\n" ); document.write( "Now consider the random variable \"X_3=%28X_1%2BX_2%29%2F2\". Do you see why \"X_3\" is the sample mean?\r
\n" ); document.write( "\n" ); document.write( "Now we can simply apply formulas and theorems to calculate each of the quantities that you have asked.
\n" ); document.write( "First, what is mean of the sample-mean? Easy. As you may know, \"mean\" of a random variable is nothing but an \"expectation\" operator \"E\" on the random variable. Therefore mean of the sample means would be \"E%28X_3%29\" which is \"E%28%28X_1%2BX_2%29%2F2%29\". Remember \"E\" is a linear operator? Which gives us \"E%28X_3%29=%28E%28X_1%29%2BE%28X_2%29%29%2F2\". What is \"E%28X_1%29\", or mean of the population? It is \"%283%2B8%2B10%2B15%29%2F4\" which is \"36%2F4=9\". What is \"E%28X_2%29\"? Well that is also 9 (Remember we are sampling with replacement?)
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