document.write( "Question 1190587: Find the tangent to f(x) = x^2 at the point where
\n" ); document.write( "i. x= 1
\n" ); document.write( "ii. x= 4\r
\n" ); document.write( "\n" ); document.write( "Please explain step-by-step!
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Algebra.Com's Answer #822288 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Part i)\r
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\n" ); document.write( "\n" ); document.write( "Use the power rule to get the derivative
\n" ); document.write( "f(x) = x^2
\n" ); document.write( "f ' (x) = 2x\r
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\n" ); document.write( "\n" ); document.write( "The derivative function will directly determine the slope of the tangent line.\r
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\n" ); document.write( "\n" ); document.write( "If x = 1, then
\n" ); document.write( "f ' (x) = 2x
\n" ); document.write( "f ' (1) = 2*1
\n" ); document.write( "f ' (1) = 2
\n" ); document.write( "The slope of the tangent is m = 2 when x = 1.\r
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\n" ); document.write( "\n" ); document.write( "Plug x = 1 into the original function
\n" ); document.write( "f(x) = x^2
\n" ); document.write( "f(1) = 1^2
\n" ); document.write( "f(1) = 1
\n" ); document.write( "The point (1,1) is on the f(x) curve.\r
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\n" ); document.write( "\n" ); document.write( "Now apply the point-slope form
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 1 = 2(x - 1)
\n" ); document.write( "y - 1 = 2x - 2
\n" ); document.write( "y = 2x-2+1
\n" ); document.write( "y = 2x-1\r
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\n" ); document.write( "\n" ); document.write( "The slope of the tangent line is y = 2x-1 when x = 1\r
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\n" ); document.write( "\n" ); document.write( "----------------------------\r
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\n" ); document.write( "\n" ); document.write( "For part ii), you'll follow very similar steps.\r
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\n" ); document.write( "\n" ); document.write( "Use f ' (x) = 2x from earlier.\r
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\n" ); document.write( "\n" ); document.write( "You should get a tangent slope of m = 8 and the point (4,16) is on the parabola.\r
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\n" ); document.write( "The equation of the tangent line is y = 8x-16 when x = 4.
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