document.write( "Question 1190567: Please help: the sum of the first two terms of a G.P is x.The sum of the last two is 1 if there are n term in all, calculate the common ratio \n" ); document.write( "
Algebra.Com's Answer #822264 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "r = common ratio\r
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\n" ); document.write( "\n" ); document.write( "Let's ignore the first two terms.\r
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\n" ); document.write( "\n" ); document.write( "The last two terms of the geometric progression (GP), aka geometric sequence, sum to 1.
\n" ); document.write( "a = second to last term
\n" ); document.write( "ar = last term\r
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\n" ); document.write( "\n" ); document.write( "a+ar = 1
\n" ); document.write( "ar = 1-a
\n" ); document.write( "r = (1-a)/a\r
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\n" ); document.write( "\n" ); document.write( "If we had
\n" ); document.write( "a = 0.2
\n" ); document.write( "for instance, then it would mean,
\n" ); document.write( "r = (1-a)/a = (1-0.2)/0.2 = 0.8/0.2 = 4
\n" ); document.write( "ar = 0.2*4 = 0.8
\n" ); document.write( "a+ar = 0.2 + 0.8 = 1\r
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\n" ); document.write( "\n" ); document.write( "Or we could have
\n" ); document.write( "a = 0.4
\n" ); document.write( "for instance, then it would mean
\n" ); document.write( "r = (1-a)/a = (1-0.4)/0.4 = 0.6/0.4 = 1.5
\n" ); document.write( "ar = 0.4*1.5 = 0.6
\n" ); document.write( "a+ar = 0.4 + 0.6 = 1\r
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\n" ); document.write( "\n" ); document.write( "As you can see, these are two examples of having two terms of a geometric sequence add to 1.
\n" ); document.write( "It turns out there are infinitely many ways to do this.\r
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\n" ); document.write( "\n" ); document.write( "It doesn't matter what those two original first terms sum to (ie. it doesn't matter what x is)
\n" ); document.write( "The problem is effectively the same as asking \"the sum of the first two terms of a GP is 1. What is the common ratio?\"\r
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\n" ); document.write( "\n" ); document.write( "In short, there are infinitely many possible solutions here. There isn't enough info to answer this current question.
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