document.write( "Question 112835: In the equation logx 4 + logx 9 = 2, what is x equal to? \n" ); document.write( "
Algebra.Com's Answer #82226 by jim_thompson5910(35256)\"\" \"About 
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\"log%28x%2C+%284%29%29+%2B+log%28x%2C+%289%29%29++=+2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%28x%2C+%284%2A9%29%29+=+2\" Combine the logarithms using the identity \"log%28b%2C+%28x%29%29+%2B+log%28b%2C+%28y%29%29=log%28b%2C%28x%2Ay%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28x%2C+%2836%29%29+=+2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=36\" Rewrite the logarithm in exponent form. In other words, use: \"log%28b%2C%28x%29%29=y\"===> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%5E2%29=sqrt%2836%29\" Now take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \r
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\n" ); document.write( "\n" ); document.write( "\"x=6\"
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