document.write( "Question 1190560: Marks of 75 students are summarised in the following frequency distribution Marks Frequency 40 - 44 7 45 - 49 10 50 - 54 22 55 - 59 F1 60 - 64 F2 65 - 69 6 70 - 74 3 If 20% of the students have marks b/n 55 and 59 find The 5th deciles, The 60th percentile, 1 quartiles
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Algebra.Com's Answer #822255 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Given data table\n" ); document.write( "\n" ); document.write( "
MarksFrequency
40 - 447
45 - 4910
50 - 5422
55 - 59F1
60 - 64F2
65 - 696
70 - 743

\n" ); document.write( "We're told that \"20% of the students have marks b/n 55 and 59\" which I'm assuming the b/n means \"between\".\r
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\n" ); document.write( "\n" ); document.write( "If 20% of the marks are between 55 and 59, then
\n" ); document.write( "20% of 75 = 0.20*75 = 15
\n" ); document.write( "This means 15 students are in the interval 55 - 59
\n" ); document.write( "We'll replace the F1 with 15\n" ); document.write( "\n" ); document.write( "
MarksFrequency
40 - 447
45 - 4910
50 - 5422
55 - 5915
60 - 64F2
65 - 696
70 - 743
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\n" ); document.write( "\n" ); document.write( "To find F2, we'll add up each of the frequencies. The total sum is 75
\n" ); document.write( "7+10+22+15+F2+6+3 = 75
\n" ); document.write( "63+F2 = 75
\n" ); document.write( "F2 = 75-63
\n" ); document.write( "F2 = 12\r
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\n" ); document.write( "\n" ); document.write( "Here's the full completed grouped frequency table\n" ); document.write( "\n" ); document.write( "
MarksFrequency
40 - 447
45 - 4910
50 - 5422
55 - 5915
60 - 6412
65 - 696
70 - 743
You should find that the frequencies sum to 75.\r
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\n" ); document.write( "\n" ); document.write( "Deciles split the data set into 10 equal pieces
\n" ); document.write( "The 5th decile is the median point because we're 5/10 = 1/2 of the way there.
\n" ); document.write( "1/2 of 75 = 75/2 = 37.5\r
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\n" ); document.write( "\n" ); document.write( "Start at the first frequency (7) and add down until we reach 37.5 or go over.
\n" ); document.write( "7 is too short
\n" ); document.write( "7+10 = 17 is too short also
\n" ); document.write( "7+10+22 = 39 we've gone over the mark of 37.5
\n" ); document.write( "The median is somewhere in the interval from 50 to 54 (when we added on that last frequency of 22)\r
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\n" ); document.write( "\n" ); document.write( "Unfortunately we don't have enough info to pinpoint exactly where the 5th decile is. I think an acceptable answer is to state the interval 50 - 54, or to state \"a score between 50 and 54\".\r
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\n" ); document.write( "\n" ); document.write( "The 60th percentile is the marker where 60% of the scores are below this value.\r
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\n" ); document.write( "\n" ); document.write( "60% of 75 = 0.60*75 = 45
\n" ); document.write( "We see that 45 students are below the 60th percentile person.\r
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\n" ); document.write( "\n" ); document.write( "Like before, we'll add up the frequencies until we hit 45 or go over.
\n" ); document.write( "7 is too short
\n" ); document.write( "7+10 = 17 is too short
\n" ); document.write( "7+10+22 = 39 is too short
\n" ); document.write( "7+10+22+15 = 54 goes overboard\r
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\n" ); document.write( "\n" ); document.write( "The 60th percentile scorer is somewhere in the interval of 55 to 59.
\n" ); document.write( "Like the previous section, we don't have enough info to pin down the exact score.\r
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\n" ); document.write( "\n" ); document.write( "The 1st quartile is equivalent to finding the 25th percentile
\n" ); document.write( "We want to know what marker has 25% of the data below this value.\r
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\n" ); document.write( "\n" ); document.write( "25% of 75 = 0.25*75 = 18.75
\n" ); document.write( "We round 18.75 to 19\r
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\n" ); document.write( "\n" ); document.write( "About 19 students are below the 25th percentile marker\r
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\n" ); document.write( "\n" ); document.write( "We'll use the same trick as the previous sections to try to get to 19 or higher
\n" ); document.write( "7 is too short
\n" ); document.write( "7+10 = 17 is too short
\n" ); document.write( "7+10+22 = 39 goes overboard\r
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\n" ); document.write( "\n" ); document.write( "The 25th percentile is in the same group as the 5th decile (aka median).
\n" ); document.write( "That group being the \"between 50 and 54\" scores.
\n" ); document.write( "Like the other sections, we don't have enough info to pin down the exact score.
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