document.write( "Question 1190435: The width of a rectangle is 25.7 feet less than four times its length, and the perimeter is 29.6 feet. Find the length and the width of the rectangle \n" ); document.write( "

Algebra.Com's Answer #822251 by ikleyn(52908) $\"\"$ $\"About$

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\n" ); document.write( "The width of a rectangle is 25.7 feet less than four times its length,
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\n" ); document.write( "\n" ); document.write( " It is to replace wrong solution from @josgarithmetic . . . \r
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document.write( "Let L be the length, in feet; then the width is  4L-25.7 feet.\r\n" );
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document.write( "Write equation for the half of the perimeter as you read the problem\r\n" );
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document.write( "   L + (4L - 25.7) = 14.8   feet   ( where 14.8 = 29.6/2 )\r\n" );
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document.write( "Simplify and find L\r\n" );
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document.write( "    5L            = 14.8 + 25.7\r\n" );
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document.write( "    5L            =     40.5\r\n" );
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document.write( "     L            =     40.5 / 5 = 8.1.\r\n" );
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document.write( "Thus the length is  8.1 feet;  the width is  4*8.1-25.7 = 6.7 feet.    ANSWER\r\n" );
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document.write( "CHECK.  The perimeter is  2*(8.1+6.7) = 2*14.8 = 29.6  ft.    ! Precisely Correct !\r\n" );
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