document.write( "Question 112836: Graph f(x) = –2x + 4. \n" ); document.write( "
Algebra.Com's Answer #82225 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=-2%2Ax%2B4\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-2
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\n" ); document.write( " \"y=-2%2A%28-2%29%2B4\"
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\n" ); document.write( " \"y=4%2B4\" Multiply
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\n" ); document.write( " \"y=8\" Add
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\n" ); document.write( " So here's one point (-2,8)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-1
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\n" ); document.write( " \"y=-2%2A%28-1%29%2B4\"
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\n" ); document.write( " \"y=2%2B4\" Multiply
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\n" ); document.write( " \"y=6\" Add
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\n" ); document.write( " So here's another point (-1,6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=-2%2Ax%2B4\" through the points (-2,8) and (-1,6)
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\n" ); document.write( " So from the graph we can see that the slope is \"-2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 1 units to get to the next point), the y-intercept is (0,\"4\")and the x-intercept is (\"2\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=4\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"4\").
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\n" ); document.write( " So we have one point (0,\"4\")
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\n" ); document.write( " Now since the slope is \"-2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"4\"), we can go down 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=-2%2Ax%2B4\"
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\n" ); document.write( " So this is the graph of \"y=-2%2Ax%2B4\" through the points (0,4) and (1,2)
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