document.write( "Question 1190542: The work W required to lift an object varies jointly with the object's mass M and the height H that the object is lifted. The work required to lift a 120-kilogram object 1.8 meters is 2,116.8 joules. Find the amount of work required to lift a 100-kilogram object 1.2 meters.
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Algebra.Com's Answer #822233 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "k = some constant
\n" ); document.write( "W = work required to lift the object
\n" ); document.write( "M = mass
\n" ); document.write( "H = height of the object\r
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\n" ); document.write( "\n" ); document.write( "The second sentence gives this info:
\n" ); document.write( "W = 2116.8 joules
\n" ); document.write( "M = 120 kg
\n" ); document.write( "H = 1.8 m\r
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\n" ); document.write( "\n" ); document.write( "Use that info to determine k
\n" ); document.write( "W = k*M*H
\n" ); document.write( "2116.8 = k*120*1.8
\n" ); document.write( "2116.8 = k*216
\n" ); document.write( "216k = 2116.8
\n" ); document.write( "k = (2116.8)/(216)
\n" ); document.write( "k = 9.8\r
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\n" ); document.write( "\n" ); document.write( "Then we can determine W if M = 100 kg and H = 1.2 m\r
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\n" ); document.write( "\n" ); document.write( "W = k*M*H
\n" ); document.write( "W = 9.8*M*H
\n" ); document.write( "W = 9.8*100*1.2
\n" ); document.write( "W = 1176\r
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\n" ); document.write( "\n" ); document.write( "Answer: 1176 joules
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