document.write( "Question 1190535: I'm having a really hard time understanding solving using elimination. Could somebody explain it to me in lots of detail.
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document.write( "x-y=3 and 2x+4y=9 \n" );
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Algebra.Com's Answer #822210 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let's multiply both sides of x-y=3 by 4 \n" ); document.write( "We should end up with 4x-4y=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The original system of \n" ); document.write( " \n" ); document.write( "is equivalent to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice how we have -4y and +4y from the first and second equations respectively. \n" ); document.write( "They add to 0y, aka 0. The y terms go away.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's add the terms straight down
\n" ); document.write( "Divide both sides by 6 to solve for x. You should get x = 21/6 = 7/2 = 3.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's plug this into any equation involving x and y, and solve for y \n" ); document.write( "x-y = 3 \n" ); document.write( "3.5-y = 3 \n" ); document.write( "-y = 3-3.5 \n" ); document.write( "-y = -0.5 \n" ); document.write( "y = 0.5 \n" ); document.write( "y = 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or, \n" ); document.write( "2x+4y = 9 \n" ); document.write( "2(3.5)+4y = 9 \n" ); document.write( "7+4y = 9 \n" ); document.write( "4y = 9-7 \n" ); document.write( "4y = 2 \n" ); document.write( "y = 2/4 \n" ); document.write( "y = 1/2 \n" ); document.write( "y = 0.5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer in fraction form: x = 7/2 and y = 1/2 \n" ); document.write( "Answer in decimal form: x = 3.5 and y = 0.5 \n" ); document.write( " \n" ); document.write( " |