document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112811>Question 112811</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321227573/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> solve the system by substitution.  Having trouble wrapping my brain around these-looked easy at first!\r<BR>\n" );
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document.write( "4x+3y=-13<BR>\n" );
document.write( "-x+ y=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82221 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4X+3Y=-13 NOW MULTIPLY THE SECOND EQUATION BY 4 & ADD,<BR>\n" );
document.write( "-4X+4Y=20<BR>\n" );
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document.write( "7Y=7<BR>\n" );
document.write( "Y=7/7<BR>\n" );
document.write( "Y=1 ANSWER.<BR>\n" );
document.write( "4X+3*1=-13<BR>\n" );
document.write( "4X+3=-13<BR>\n" );
document.write( "4X=-13-3<BR>\n" );
document.write( "4X=-16<BR>\n" );
document.write( "X=-16/4<BR>\n" );
document.write( "X=-4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );