document.write( "Question 112773: Solve the system by addition or substitution.
\n" ); document.write( " 3x – 4y = 8
\n" ); document.write( " 6x – 2y = 10
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #82210 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Solving by addition:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply \"3x-4y=8\" by \"-2\", resulting in:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-6x%2B8y=-16\". (Why did I do this step? Multiplying by a -2 caused the x coefficient to become -6 in this equation so that when we add the two equations, the coefficient on the x term will become zero. We could just as well have multiplied the second equation by -2 so that the coefficent on the y term would have become -4 and when the two equations were added, the y term coefficient would have become zero. The arithmetic would be a little different in that case, but the ultimate answer would still be the same. I'll leave trying it as an exercise for you.)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now add the two equations, term by term (the x terms to the x terms, the y terms to the y terms, etc.), resulting in:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0x%2B6y=-6\"
\n" ); document.write( "\"6y=-6\"
\n" ); document.write( "\"y=-1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then substitute the value of y in either of the equations and solve for x:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x-4%28-1%29=8\"
\n" ); document.write( "\"3x%2B4=8\"
\n" ); document.write( "\"3x=8-4\"
\n" ); document.write( "\"x=4%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%284%2F3%29-4%28-1%29=8\", \"4%2B4=8\"
\n" ); document.write( "\"6%284%2F3%29-2%28-1%29=10\",\"8%2B2=10\", and the answer checks.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve by substitution:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x-4y=8\"
\n" ); document.write( "\"6x-2y=10\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First, rearrange one of the equations so that one of the variable is expressed as a function of the other. I'll solve the first equation for y. (Again, it doesn't matter which variable you choose to solve for here -- if you do your arithmetic carefully and follow all of the algebra rules, you get the same answer in the end.)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x-4y=8\"
\n" ); document.write( "\"-4y=-3x%2B8\"
\n" ); document.write( "\"y=%28-3x%29%2F%28-4%29%2B8%2F-4\"
\n" ); document.write( "\"y=3x%2F4-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Second, substitute this expression for y into the second equation:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"6x-2%283x%2F4-2%29=10\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And then solve for x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"6x-2%283x%2F4-2%29=10\"
\n" ); document.write( "\"6x-3x%2F2%2B4=10\"
\n" ); document.write( "\"6x-3x%2F2=10-4\"
\n" ); document.write( "\"12x%2F2-3x%2F2=6\"
\n" ); document.write( "\"9x%2F2=6\"
\n" ); document.write( "\"9x=12\"
\n" ); document.write( "\"x=12%2F9=4%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Finally, substitute this value for x into either equation and solve for y:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%284%2F3%29-4y=8\"
\n" ); document.write( "\"4-4y=8\"
\n" ); document.write( "\"-4y=8-4\"
\n" ); document.write( "\"y=-1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(4/3,-1) is the solution that we got when we did the problem by addition and we have already checked this answer so you are done.
\n" ); document.write( "
\n" ); document.write( "
\n" );