document.write( "Question 1190432: Bob is three times as old as Jenny, who is five times as old as Lou. If Bob is x
\n" ); document.write( "years old, then in ten years how old will Lou be in terms of x?
\n" ); document.write( "a) x/(5+10)
\n" ); document.write( "b) (x+2)/2
\n" ); document.write( "c) (x+6)/3
\n" ); document.write( "d) (3x)/(5+10)
\n" ); document.write( "e) x/(3+10)\r
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Algebra.Com's Answer #822073 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The question doesn't ask for any ages; it only asks for an expression for Lou's age in terms of x, which is Bob's age.

\n" ); document.write( "x = Bob
\n" ); document.write( "(1/3)x = Jenny (Bob is 3 times as old as Jenny)
\n" ); document.write( "(1/15)x = Lou (Jenny is 5 times as old as Lou)

\n" ); document.write( "(1/15)x+10 = Lou's age in 10 years

\n" ); document.write( "None of the given answer choices is equivalent to that, so the problem is faulty.

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