document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190410>Question 1190410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a restaurant sells fries for RS 120 each.burger for RS 200 each and sandwitches for RS 250 each if the profit on fries is 1/3 of its selling price ,profit on burgers is RS 60 more than the profit on fries and profit on sandwiches is 125% of profit on burgers what will be the total profit for the sale of 5 fries 10 burgers and 15 sandwitches </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #822069 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=822069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "profit on each fries: 1/3 of the selling price of RS 120 = RS 40<br><BR>\n" );
document.write( "profit on each burger: RS 60 more than on fries = RS 40 + RS 60 = RS 100<br><BR>\n" );
document.write( "profit on each sandwich: 125% of the profit on burgers = 1.25(RS 100) = RS 125<br><BR>\n" );
document.write( "profit on 5 fries, 10 burgers, and 15 sandwiches: 5(40)+10(100)+15(125)=200+1000+1875 = 3075<br><BR>\n" );
document.write( "ANSWER: RS 3075<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );