document.write( "Question 1190279: Solve 3cos(x+40°) = 4sin(x+40°) for 0° ≤ x ≤ 360° \n" ); document.write( "

Algebra.Com's Answer #822025 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Solve $\"3cos%28x%2B40%29+=+4sin%28x%2B40%29\"$ for $\"0\"$ ° ≤ $\"x\"$ ≤ $\"360\"$ °
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\n" ); document.write( "\n" ); document.write( " Below find the correct solution to replace the incorrect one from @MathLover1.\r
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\n" ); document.write( "\n" ); document.write( " $\"3cos%28x%2B40%29\"$ = $\"4sin%28x%2B40%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"3%2F4\"$ = $\"sin%28x%2B40%5Eo%29+%2Fcos%28x%2B40%5Eo%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"tan%28x%2B40%29\"$ = $\"3%2F4\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B40\"$ = $\"tan%5E%28-1%29%283%2F4%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "x = $\"tan%5E%28-1%29%283%2F4%29-40\"$ ° \r
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\n" ); document.write( "\n" ); document.write( "solutions: \r
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\n" ); document.write( "\n" ); document.write( "x = $\"tan%5E-1%283%2F4%29-40+%2B+180%2An\"$ ° \r
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\n" ); document.write( "\n" ); document.write( "for range $\"0\"$ ° ≤ $\"x\"$ ≤ $\"360\"$ °\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5B1%5D\"$ = $\"36.87-40%2B180\"$ ° = 176.87°;\r
\n" ); document.write( "\n" ); document.write( " $\"x%5B2%5D\"$ = $\"36.87-40%2B360\"$ ° = 356.87°.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER. Two solutions are 176.87° and 356.87° (both are approximate and rounded).
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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