document.write( "Question 1190385: Assuming the normal heart rate (H.R) in normal healthy individuals is normally distributed with
\n" ); document.write( "Mean = 70 and Standard Deviation =10 beats/min.
\n" ); document.write( "a) What is the probability that the heart rate is above 80 beats/min?
\n" ); document.write( "b) What is the probability that the heart rate is above 90 beats/min?
\n" ); document.write( "c) What is the probability that the heart rate is between 50-90 beats/min?
\n" ); document.write( "d) What is the probability that the heart rate is above 100 beats/min?
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Algebra.Com's Answer #822008 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "mu = 70 = population mean
\n" ); document.write( "sigma = 10 = population standard deviation\r
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\n" ); document.write( "\n" ); document.write( "Convert x = 80 to its corresponding z score
\n" ); document.write( "z = (x-mu)/sigma
\n" ); document.write( "z = (80-70)/10
\n" ); document.write( "z = 10/10
\n" ); document.write( "z = 1\r
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\n" ); document.write( "\n" ); document.write( "The question of asking P(X > 80) is identical to P(Z > 1) when we have the parameters of mu = 70 and sigma = 10.\r
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\n" ); document.write( "\n" ); document.write( "Use a Z table in the back of your textbook to find that
\n" ); document.write( "P(Z < 1) = 0.84134\r
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\n" ); document.write( "\n" ); document.write( "Here's a free Z table if you don't have your stats textbook with you
\n" ); document.write( "https://www.ztable.net/\r
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\n" ); document.write( "\n" ); document.write( "From that we could say:
\n" ); document.write( "P(Z > 1) = 1 - P(Z < 1)
\n" ); document.write( "P(Z > 1) = 1 - 0.84134
\n" ); document.write( "P(Z > 1) = 0.15866\r
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\n" ); document.write( "\n" ); document.write( "Answer: Approximately 0.15866\r
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\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "You'll follow the same steps as the previous part.
\n" ); document.write( "x = 90 converts to z = 2. I'm skipping steps a bit.
\n" ); document.write( "P(X > 90) is equivalent to P(Z > 2)\r
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\n" ); document.write( "\n" ); document.write( "Use the table to find that
\n" ); document.write( "P(Z < 2) = 0.97725
\n" ); document.write( "So,
\n" ); document.write( "P(Z > 2) = 1 - P(Z < 2)
\n" ); document.write( "P(Z > 2) = 1 - 0.97725
\n" ); document.write( "P(Z > 2) = 0.02275\r
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\n" ); document.write( "\n" ); document.write( "Answer: Approximately 0.02275\r
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\n" ); document.write( "Part (c)\r
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\n" ); document.write( "\n" ); document.write( "x = 50 converts to z = -2
\n" ); document.write( "x = 90 converts to z = 2\r
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\n" ); document.write( "\n" ); document.write( "Computing P(50 < X < 90) is equivalent to P(-2 < Z < 2)\r
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\n" ); document.write( "\n" ); document.write( "The table shows that
\n" ); document.write( "P(Z < -2) = 0.02275
\n" ); document.write( "P(Z < 2) = 0.97725\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This leads to:
\n" ); document.write( "P(a < Z < b) = P(Z < b) - P(Z < a)
\n" ); document.write( "P(-2 < Z < 2) = P(Z < 2) - P(Z < -2)
\n" ); document.write( "P(-2 < Z < 2) = 0.97725 - 0.02275
\n" ); document.write( "P(-2 < Z < 2) = 0.9545
\n" ); document.write( "This fits with the Empirical Rule which says roughly 95% of the normal distribution is within 2 standard deviations of the mean.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer: Approximately 0.9545\r
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\n" ); document.write( "Part (d)\r
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\n" ); document.write( "\n" ); document.write( "x = 100 converts to z = 3
\n" ); document.write( "P(Z < 3) = 0.99865
\n" ); document.write( "P(Z > 3) = 1 - P(Z < 3)
\n" ); document.write( "P(Z > 3) = 1 - 0.99865
\n" ); document.write( "P(Z > 3) = 0.00135\r
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\n" ); document.write( "\n" ); document.write( "Answer: Approximately 0.00135\r
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\n" ); document.write( "\n" ); document.write( "You can use a normalCDF calculator to compute the more accurate versions of each approximate answer above.
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