document.write( "Question 112780: Anne and Nancy use a metal alloy that is 24.9% copper to make jewelry. How many ounces of a 20% alloy must be mixed with a 27% alloy to form 100 ounces of the desired alloy? \n" ); document.write( "
Algebra.Com's Answer #82200 by SHUgrad05(58)\"\" \"About 
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Let x= 20% alloy; y= 27% alloy
\n" ); document.write( "Set up system of equations:
\n" ); document.write( ".20x+.27y=24.9
\n" ); document.write( " x+y=100 -->multiply by -.20\r
\n" ); document.write( "\n" ); document.write( " .20x+.27y=24.9
\n" ); document.write( "-.20x+-.20y=-20.00
\n" ); document.write( " .07y=4.9
\n" ); document.write( " y=70 -->plug back into one of the original equations\r
\n" ); document.write( "\n" ); document.write( "x+70=100
\n" ); document.write( "x=30\r
\n" ); document.write( "\n" ); document.write( "30 ounces of 20% alloy; 70 ounces of 27% alloy
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