document.write( "Question 1190368: How do I factor x^3-4x^2+x+6 to find out the solutions?\r
\n" ); document.write( "\n" ); document.write( "I was given that x=-2 is one of the solutions.\r
\n" ); document.write( "\n" ); document.write( "The factoring is what is giving me trouble.
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Algebra.Com's Answer #821982 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"+x%5E3-4x%5E2%2Bx%2B6\"\r
\n" ); document.write( "\n" ); document.write( "if given that \"x=-2\" is one of the solutions, means \"%28x-%28-2%29%29\"=\"x%2B2\" is one factor\r
\n" ); document.write( "\n" ); document.write( "so, use long division to see if you can factor it completely\r
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\n" ); document.write( "\n" ); document.write( "---------(\"x%5E2-6x%2B13\"
\n" ); document.write( "\"%28x%2B2%29\"|\"+x%5E3-4x%5E2%2Bx%2B6\"
\n" ); document.write( "----------\"+x%5E3%2B2x%5E2\".........subtract
\n" ); document.write( "-------------\"+-6x%5E2\"....bring \"x\" down
\n" ); document.write( "-------------\"+-6x%5E2%2Bx\"
\n" ); document.write( "-------------\"+-6x%5E2-12x\"........subtract
\n" ); document.write( "-------------------\"+13x\"...bring \"6\" down
\n" ); document.write( "-------------------\"+13x%2B6\"
\n" ); document.write( "-------------------\"+13x%2B26\".......subtract
\n" ); document.write( "----------------------\"+-20\"->reminder\r
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\n" ); document.write( "\n" ); document.write( "\"+x%5E3-4x%5E2%2Bx%2B6=%28x%5E2-6x%2B13%29%28x%2B2%29%2B%28-20%29\"\r
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