document.write( "Question 1190367: Having trouble figuring out how to factor this problem.\r
\n" ); document.write( "\n" ); document.write( "Factor completely given that x-3 is a factor of x^3-5x^2-14x+60.\r
\n" ); document.write( "\n" ); document.write( "I tried grouping to factor and it isn't working.
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Algebra.Com's Answer #821980 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "given that\"x-3\" is a factor of\r
\n" ); document.write( "\n" ); document.write( "\"x%5E3-5x%5E2-14x%2B6\"\r
\n" ); document.write( "\n" ); document.write( "use long division to see if it could be factored completely\r
\n" ); document.write( "\n" ); document.write( "if we got reminder, than it's not possible to factor completely\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------(\"x%5E2-2x-20\"
\n" ); document.write( "\"%28x-3%29\"|\"x%5E3-5x%5E2-14x%2B6\"
\n" ); document.write( "---------------\"x%5E3-3x%5E2\".....subtract
\n" ); document.write( "-------------------\"-2x%5E2\".....bring \"-14x\" down
\n" ); document.write( "-------------------\"-2x%5E2-14x\"
\n" ); document.write( "-------------------\"-2x%5E2%2B6x\"....subtract
\n" ); document.write( "----------------------------\"-20x\"....bring \"6\" down
\n" ); document.write( "-----------------------------\"-20x%2B6\"
\n" ); document.write( "-----------------------------\"-20x%2B60\"....subtract
\n" ); document.write( "-------------------------------------\"-54\"->reminder\r
\n" ); document.write( "\n" ); document.write( "so,\r
\n" ); document.write( "\n" ); document.write( "\"x%5E3+-+5+x%5E2+-+14+x+%2B+6+=+%28x%5E2+-+2+x+-+20%29%28x+-+3%29+%2B+%28-54%29\"\r
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