document.write( "Question 112700: I had to solve a quadratic equation by factoring and I recived it back as incorect. I dont know what I did wrong...could someone please explain this to me and show the correct steps if possible. I did not get 2 solutions for x and I cant figure out how to do this.
\n" ); document.write( " Thanks so much.\r
\n" ); document.write( "\n" ); document.write( "3x^2+11x-20=0
\n" ); document.write( "3x^2+15x-4x-20=0
\n" ); document.write( "3x(x+15)-4(x+5)=0
\n" ); document.write( "(3x-4)(x+5=0)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #82197 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"3x%5E2%2B11x-20=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B15x-4x-20=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%28x%2B15%29-4%28x%2B5%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283x-4%29%28x%2B5%29=0\"....well done up to here...\r
\n" ); document.write( "\n" ); document.write( "now, the product above will be equal to \"0\" if one or both factors are equal to \"0\"\r
\n" ); document.write( "\n" ); document.write( "let find out what are values for \"x%5B1%2C2%5D\":\r
\n" ); document.write( "\n" ); document.write( "\"3x+-+4+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+=+4\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+4%2F3\"\r
\n" ); document.write( "\n" ); document.write( "if \"x+=+1.33\"........first solution\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "if \"x+=+-5\".........second solution
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );