document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190333>Question 1190333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From the top of a lighthouse 60m high, a boat with an angle of depression of 37° If the boat travels linearly 35m towards the tower. What is the new angle of<BR>\n" );
document.write( " elevation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #821954 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=821954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the top of a lighthouse 60m high, a boat with an angle of depression of 37° If the boat travels linearly 35m towards the tower. What is the new angle of<BR>\n" );
document.write( " elevation?<BR>\n" );
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document.write( "tan(37) = 60/d where d is the distance from the base of the lighthouse to the boat.<BR>\n" );
document.write( "d = 60/tan(37) = ~ 79.62 meters<BR>\n" );
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document.write( "After moving 35 meters,<BR>\n" );
document.write( "tan(A) = 60/(79.62-35)<BR>\n" );
document.write( "A = ~ 53.36 degs, the angle of depression from the lighthouse, not angle of elevation. </SPAN>\n" );
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