document.write( "Question 1190332: The mean useful life of car batteries is 55 months. They have a standard deviation of 2. Assume the useful life of batteries is normally distributed.\r
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\n" ); document.write( "\n" ); document.write( "a. Calculate the percent of batteries with a useful life of less than 51 months. (Round your answer to the nearest hundredth percent.)
\n" ); document.write( "b. Calculate the percent of batteries that will last longer than 61 months. (Round your answer to the nearest hundredth percent.)\r
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Algebra.Com's Answer #821953 by Theo(13342)\"\" \"About 
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mean = 55
\n" ); document.write( "standard deviation = 2
\n" ); document.write( "z-score = (x - m) / s
\n" ); document.write( "x = the raw score = 51
\n" ); document.write( "m = the mean = 55
\n" ); document.write( "s = standard deviation = 2\r
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\n" ); document.write( "\n" ); document.write( "for part a ....\r
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\n" ); document.write( "\n" ); document.write( "z = (x - m) / s becomes z = (51 - 55) / 2 = -4 / 2 = -2
\n" ); document.write( "area to the left of z-score of -2 = .02275
\n" ); document.write( "rounded to 4 decimal places to bet .0228 = 2.28%.\r
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\n" ); document.write( "\n" ); document.write( "for part b ....\r
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\n" ); document.write( "\n" ); document.write( "z = (x - m) / s becomes z = (61 - 55) / 2 = 6/2 = 3
\n" ); document.write( "area to the left of z-score of 3 = .99865.
\n" ); document.write( "area to the right of z-score of 3 = 1 - .99865 = .00135.
\n" ); document.write( "round to 4 decimal places to get .0014 = .14%.\r
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\n" ); document.write( "\n" ); document.write( "i used the following z-score table to get these figures.\r
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\n" ); document.write( "\n" ); document.write( "https://www.rit.edu/academicsuccesscenter/sites/rit.edu.academicsuccesscenter/files/documents/math-handouts/Standard%20Normal%20Distribution%20Table.pdf\r
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\n" ); document.write( "\n" ); document.write( "using the ti-85 plus calculator, i got:\r
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\n" ); document.write( "\n" ); document.write( "area to the left of z-score of -2 = .022750062.
\n" ); document.write( "rounded to 4 decimal places = .0228 = 2.28%.\r
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\n" ); document.write( "\n" ); document.write( "area to the left of z-score of 3 = .9986500328.
\n" ); document.write( "area to the right of z-score of 3 = 1 minus .9986500328 = .0013499672.
\n" ); document.write( "rounded to 4 decimal places = .0013 = .13%.\r
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\n" ); document.write( "\n" ); document.write( "the discrepancy between .13% and .14% has to do with the table figures being rounded to 5 decimal places while the calculator figures are being rounded to 7 or 8 decimal places.
\n" ); document.write( "the difference affected the rounding to 4 decimal places in this case.
\n" ); document.write( "it's a small difference, but it is a difference.
\n" ); document.write( "if you go by the table, then .14% is more accurate.\r
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