document.write( "Question 1190312: Find the area, in square units, of an isosceles triangle whose sides have lengths 29, 29, and 42 cm without using Heron's formula \n" ); document.write( "

Algebra.Com's Answer #821930 by ikleyn(52775) $\"\"$ $\"About$

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\n" ); document.write( "Find the area, in square units, of an isosceles triangle whose sides have lengths
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document.write( "In isosceles triangle, the altitude drawn to the base, is the median at the same time.\r\n" );
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document.write( "It means that the altitude divides the triangle in two congruent right anfled triangle.\r\n" );
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document.write( "So, we can find the altitude length h in this way by applying thr Pythagorean formula \r\n" );
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document.write( "    h =  =  =  = 20.\r\n" );
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document.write( "Then the area of the given triangle is half the product of the base by the altitude\r\n" );
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document.write( "    the area =  = 42*10 = 420 square centimeters.    ANSWER\r\n" );
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