document.write( "Question 1190296: Phyllis invested
\n" );
document.write( "56000
\n" );
document.write( " dollars, a portion earning a simple interest rate of
\n" );
document.write( "5
\n" );
document.write( " percent per year and the rest earning a rate of
\n" );
document.write( "6
\n" );
document.write( " percent per year. After one year the total interest earned on these investments was
\n" );
document.write( "3200
\n" );
document.write( " dollars. How much money did she invest at each rate? \n" );
document.write( "
Algebra.Com's Answer #821928 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A quick, informal solution method, if formal algebra is not required.... \n" ); document.write( "$56000 all invested at 5% would yield $2800 interest; all invested at 6% would yield $3360 interest. The ratio in which the total was split between the two investments is determined by where the actual interest of $3200 lies between $2800 and $3360. \n" ); document.write( "(1) Look at the three interest amounts 2800, 3200, and 3360 on a number line and observe/calculate that 3200 is 400/560 = 5/7 of the way from 2800 to 3360. \n" ); document.write( "(2) That means 5/7 of the total was invested at the higher rate. \n" ); document.write( "ANSWER: 5/7 of the total $56,000, or $40,000, was invested at 6%; the other $16,000 at 5%. \n" ); document.write( "CHECK: .06(40,000)+.05(16,000) = 2400+800 = 3200 \n" ); document.write( " \n" ); document.write( " |