document.write( "Question 1190296: Phyllis invested
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document.write( "56000
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document.write( " dollars, a portion earning a simple interest rate of
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document.write( "5
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document.write( " percent per year and the rest earning a rate of
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document.write( "6
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document.write( " percent per year. After one year the total interest earned on these investments was
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document.write( "3200
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document.write( " dollars. How much money did she invest at each rate? \n" );
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Algebra.Com's Answer #821911 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x at 5% makes 0.05x per year (dollars) \n" ); document.write( "56000-x at 6% makes 3360-0.06x per year \n" ); document.write( "they add to 3200 \n" ); document.write( "so 3200=-0.01x+3360 \n" ); document.write( "0.01x=-160 \n" ); document.write( "x=$16000 @5%=$800 \n" ); document.write( "56000-x=40000@6%=$2400 \n" ); document.write( "they add to $3200. \n" ); document.write( " |