document.write( "Question 16798: Find the polynmial f(x) of degree three that has zeroes at 1, 2 and 4 such that f(0)=-16.
\n" ); document.write( "


\n" ); document.write( "I think it should be f(x)=d(x-1)(x-2)(x-4) so d(0-1)(0-2)(0-4) = f(0) = -16
\n" ); document.write( "So -6d = -16
\n" ); document.write( "d = 8/3
\n" ); document.write( "


\n" ); document.write( "I'm not sure if I'm right so far and not when I plugged things in to the equation above I didn't get anything remotely right. Please help.\r
\n" ); document.write( "\n" ); document.write( "Thanks \n" ); document.write( "


Algebra.Com's Answer #8219 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
It looks like you did it right. There is just one very small error in your solution:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I think it should be f(x)=d(x-1)(x-2)(x-4) so d(0-1)(0-2)(0-4) = f(0) = -16
\n" ); document.write( "So -6d = -16
\n" ); document.write( "d = 8/3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "How about -8d = -16??
\n" ); document.write( "d= 2!!\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );