document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190209>Question 1190209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The manager of the Sweet Candy Shop wishes to mix candy worth $4 per pound, $6 per pound, and $10 per pound to get 100 pounds of a mixture worth $7.60 per pound. The amount of $10 candy must equal the total amounts of the $4 and the $6 candy. How many pounds of each must be used? </SPAN>\n" );
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document.write( "The amount of $10 candy is equal to the total amounts of the $4 and $6 candy; and the total amount of candy is 100 pounds.  Therefore, there are 50 pounds of the $10 candy.<br><BR>\n" );
document.write( "The 50 pounds of the $10 candy are worth $500; the total 100 pounds of the mixture at $7.60 per pound is worth $760.  So the value of the combined $4 and $6 candy is $260.<br><BR>\n" );
document.write( "50 pounds of $4 coffee would be worth $200; 50 pounds of $6 coffee would be worth $300; the actual value of the $4 and $6 candy together is $260.<br><BR>\n" );
document.write( "Look at the three values $200, $260, and $300 on a number line and observe/calculate that 260 is 60/100 = 3/5 of the way from 200 to 300.  That means 3/5 of the 50 pounds of $4 and $6 candy must be the $6 candy.<br><BR>\n" );
document.write( "So there is 3/5 of 50 pounds, or 30 pounds, of $6 candy and 20 pounds of $4 candy.<br><BR>\n" );
document.write( "ANSWER: 50 pounds of $10 candy, 30 pounds of $6 candy, and 20 pounds of $4 candy<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "50(10)+30(6)+20(4) = 500+180+80 = 760<BR>\n" );
document.write( "100(7.60) = 760<br><BR>\n" );
document.write( " </SPAN>\n" );
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