document.write( "Question 1190207: A full box of ball bearings weighs 21 pounds. The box plus 1/3 of the ball bearings weighs 9 pounds. How much does the box alone weigh?
\n" ); document.write( "A) 4 pounds
\n" ); document.write( "B) 3 pounds
\n" ); document.write( "C) 5 pounds
\n" ); document.write( "D) 6 pounds
\n" ); document.write( "E) 2 pounds\r
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Algebra.Com's Answer #821798 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Let's say there are 90 ball bearings in total.
\n" ); document.write( "I picked something that's a multiple of 3, so that 1/3 of it is some whole number.\r
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\n" ); document.write( "\n" ); document.write( "1/3 of this is (1/3)*90 = 30 ball bearings.\r
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\n" ); document.write( "\n" ); document.write( "x = weight of the empty box
\n" ); document.write( "b = weight of 30 ball bearings
\n" ); document.write( "3b = weight of 90 ball bearings
\n" ); document.write( "All weight expressions are in pounds.\r
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\n" ); document.write( "\n" ); document.write( "Based on the given info provided by your teacher, we can form these two equations
\n" ); document.write( "x+3b = 21
\n" ); document.write( "x+b = 9\r
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\n" ); document.write( "\n" ); document.write( "Subtract the equations straight down
\n" ); document.write( "The x terms cancel and we are left with this equation
\n" ); document.write( "2b = 12
\n" ); document.write( "It solves to b = 6 after dividing both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "We can then say,
\n" ); document.write( "x+b = 9
\n" ); document.write( "x+6 = 9
\n" ); document.write( "x = 9-6
\n" ); document.write( "x = 3
\n" ); document.write( "Or you could say
\n" ); document.write( "x+3b = 21
\n" ); document.write( "x+3*6 = 21
\n" ); document.write( "x+18 = 21
\n" ); document.write( "x = 21-18
\n" ); document.write( "x = 3\r
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\n" ); document.write( "\n" ); document.write( "Answer: B) 3 pounds
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