document.write( "Question 1190104: In 2003, a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly. Answer the questions below and to earn full credit show all work/calculations/thinking.\r
\n" ); document.write( "\n" ); document.write( "How much did the population grow between the year 2003 and 2007?
\n" ); document.write( "How long did it take the population to grow from 1431 people to 2134 people?
\n" ); document.write( "What is the average population growth per year?
\n" ); document.write( "What was the population in the year 2000?
\n" ); document.write( "Find an equation for the population, P, of the town t years after 2000.
\n" ); document.write( "Using your equation, predict the population of the town in 2014.
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Algebra.Com's Answer #821764 by Boreal(15235)\"\" \"About 
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In 4 years it grew 703.
\n" ); document.write( "It took 4 years, although I am interpreting from the same point in 2003 to the same point in 2007. If it were 1/1/03 to 12/31/07, it would obviously be 5 years.
\n" ); document.write( "average growth/yr is 703/4=175.75 people/yr
\n" ); document.write( "in 2000 3 years earlier, it was 3*175.75 fewer or 527 people or 904 people.
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\n" ); document.write( "this would be 904+175.75t where t=years after 2000
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\n" ); document.write( "in 2014 it would be 175.75*7=1230.25 or 1230 people more or 3364 people.
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\n" ); document.write( "(3, 1431)(7,2134)
\n" ); document.write( "slope is 175.75
\n" ); document.write( "point slope formula y-y1=m(x-x1) m slope (x1, y1) point
\n" ); document.write( "y-1431=175.75(x-3)
\n" ); document.write( "y=175.75 x +904 where x is the years after 2000.
\n" ); document.write( "when x=14 y=3364.5, so depending on where one rounds, it is 3364 or 3365 people.
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