document.write( "Question 1190117: A construction company purchases a bull-
\n" ); document.write( "dozer for $160,000. Each year the value of the bulldozer
\n" ); document.write( "depreciates by 20% of its value in the preceding year. Let V,
\n" ); document.write( "be the value of the bulldozer in the nth year. (Let n = 1 be
\n" ); document.write( "the year the bulldozer is purchased.) \n" ); document.write( "

Algebra.Com's Answer #821756 by Boreal(15235) $\"\"$ $\"About$

You can put this solution on YOUR website!
end of first year value is 160000*0.8 or (1-0.2)^2. The two is the value at the end of the first year, when it was purchased. \r
\n" ); document.write( "\n" ); document.write( "V(n)=160000*0.8^(n-1)
\n" ); document.write( " \n" ); document.write( "

\n" );