document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190135>Question 1190135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, please help me out!\r<BR>\n" );
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document.write( "A bag contains 8 blue, 7 red, 5 pink and 10 orange jelly beans. Six jellybeans are to be selected at random without replacement.\r<BR>\n" );
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document.write( "A. What type of distribution is this? (Uniform, Binomial, Geometric, or Hypergeometric)\r<BR>\n" );
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document.write( "B. What is the probability that at least one of the jelly beans picked is orange?\r<BR>\n" );
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document.write( "C. What is the expected number of pink jelly beans to be selected? (Which expectance formula should I use? They all vary for the type of distribution so I am confused) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #821751 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=821751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6 out of 30 is 30C6 possibilities<BR>\n" );
document.write( "for pink NOT to be chosen at all, the probability is 25C6*5C0/30C6=0.2983, so the answer is the complement or 0.7017.<BR>\n" );
document.write( "Also can be done by brute force with probability not is 25/30*24/29*23/28*22/27*21/26*20/25, which also equals 0.2983 with complement 0.7017, which is the answer.<BR>\n" );
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document.write( "E(x)=nK/N=6*5/30; the number of \"good,\" if you will (5)*number of trials divided by total number.<BR>\n" );
document.write( "=30/30, or 1<BR>\n" );
document.write( "Brute force:<BR>\n" );
document.write( "probability of 0 being chosen is 0.2983<BR>\n" );
document.write( "probability of 1 is 5C1*25C5/30C6=0.4474<BR>\n" );
document.write( "probability of 2 is 5C2*25C4/30C6=0.2130<BR>\n" );
document.write( "of 3 is 0.0387<BR>\n" );
document.write( "of 4 is 0.0025<BR>\n" );
document.write( "of 5 is <0.0001<BR>\n" );
document.write( "and x*p(x) summed will be 1.0 allowing rounding.<BR>\n" );
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