document.write( "Question 112700: I had to solve a quadratic equation by factoring and I recived it back as incorect. I dont know what I did wrong...could someone please explain this to me and show the correct steps if possible. I did not get 2 solutions for x and I cant figure out how to do this.
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\n" ); document.write( "\n" ); document.write( "3x^2+11x-20=0
\n" ); document.write( "3x^2+15x-4x-20=0
\n" ); document.write( "3x(x+15)-4(x+5)=0
\n" ); document.write( "(3x-4)(x+5=0)
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Algebra.Com's Answer #82175 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%283x-4%29%28x%2B5%29=0\" I'm going to start where you left off\r
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\n" ); document.write( "\n" ); document.write( "\"3x-4=0\" or \"x%2B5=0\" Set each factor equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=4%2F3\" or \"x=-5\" Solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our solution is \"x=4%2F3\" or \"x=-5\"
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