document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190163>Question 1190163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the perimeter of a rectangle that's in a circle when all I know is the diameter (6 inches) and the area of the square (15). I've been at this for a week please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #821737 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=821737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A square of area 15 can't be inscribed in a circle of diameter 6; so I will assume that the area of 15 is of a rectangle -- as suggested in the first phrase of your post -- instead of the area of a square.<br><BR>\n" );
document.write( "Let x be one dimension of the rectangle<BR>\n" );
document.write( "Then 15/x is the other dimension<br><BR>\n" );
document.write( "The diameter of the circle is the diagonal of the rectangle:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%5E2%2B%2815%2Fx%29%5E2%29=6 ALIGN=MIDDLE  ALT=\"sqrt%28x%5E2%2B%2815%2Fx%29%5E2%29=6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B225%2Fx%5E2=36 ALIGN=MIDDLE  ALT=\"x%5E2%2B225%2Fx%5E2=36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-36%2B225%2Fx%5E2=0 ALIGN=MIDDLE  ALT=\"x%5E2-36%2B225%2Fx%5E2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E4-36x%5E2%2B225=0 ALIGN=MIDDLE  ALT=\"x%5E4-36x%5E2%2B225=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The equation does not factor over the integers, so use a numerical method or a graphing calculator to find the possible values of x.  I leave that to you.<br><BR>\n" );
document.write( "Note the equation is an even function.  It has four zeros -- two positive values and the opposites of those two.<br><BR>\n" );
document.write( "Obviously the negative solutions make no sense in the problem.<br><BR>\n" );
document.write( "The two positive solutions are the two dimensions of the rectangle.<br><BR>\n" );
document.write( "Use those dimensions to find the perimeter.<br><BR>\n" );
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