document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1190160>Question 1190160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> With 2 inflowing pipes open, a water tank can be filled in four hours. if the larger pipe can fill the tank alone in 7 hours, how long would the smaller pipe take to fill the tank? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #821736 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=821736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor showed a solution using the standard algebraic method.  Here is an alternative method.<br><BR>\n" );
document.write( "Consider the least common multiple of the two times, which is 28 hours.<br><BR>\n" );
document.write( "In 28 hours, the two pipes together could fill 28/4=7 of those tanks; in 28 hours the large pipe alone could fill 28/4=7 of those tanks.<br><BR>\n" );
document.write( "That means in 28 hours the smaller pipe could fill 7-4=3 of those tanks; and that in turn means it would take the smaller pipe 28/3 hours, or 9 1/3 hours, to fill the one tank by itself.<br><BR>\n" );
document.write( "ANSWER: 9 1/3 hours<br><BR>\n" );
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