document.write( "Question 1190094: If a = $.01, b = $.02, c = $.03, and so on, what is the value of your first name? Using this alphabet system, one of the days of the week is worth exactly $1.00. Which is it? Explain your reasoning.
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Algebra.Com's Answer #821668 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The names of the days all have the common suffix \"day\".\r
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\n" ); document.write( "\n" ); document.write( "It costs 4 + 1 + 25 = 30 cents.\r
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\n" ); document.write( "\n" ); document.write( "So, we should combine 70 cents using the rest of letters.\r
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\n" ); document.write( "\n" ); document.write( "Since any letter costs not more than 26 cents (and 13.5 cents, in average, because there are 26 letters in English alphabet),
\n" ); document.write( "it makes it clear than 3 remaining letters, as in the word \"Monday\", is not enough.\r
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\n" ); document.write( "\n" ); document.write( "So, Monday, Friday and Sunday do not work.\r
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\n" ); document.write( "\n" ); document.write( "Also, thinking this way, it is obvious that the words with 4 or 5 leading letters, like Tuesday or Thursday, have few chances, too.\r
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\n" ); document.write( "\n" ); document.write( "So, only Wednesday and Saturday are the real candidates to be verified in the first turn,\r
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\n" ); document.write( "\n" ); document.write( "and it REDUCES the choice to be checked.\r
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\n" ); document.write( "\n" ); document.write( "It is my semi-joking answer to this joke problem . . . \r
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