document.write( "Question 1190085: Write an exponential function in the form y=ab^x
\n" ); document.write( " that goes through points (0, 12) and (2,768)
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Algebra.Com's Answer #821642 by Theo(13342)\"\" \"About 
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your points are (0,12) and (2,768).
\n" ); document.write( "your equation is y = a * b ^ x.
\n" ); document.write( "12 is the value of y when x is equal to 0.
\n" ); document.write( "you get 12 = a * b^0 which becomes:
\n" ); document.write( "12 = a * 1 which becomes:
\n" ); document.write( "12 = a.
\n" ); document.write( "the equation becomes y = 12 * b ^ x.
\n" ); document.write( "y = 768 when x = 2.
\n" ); document.write( "the equation becomes 768 = 12 * b^2.
\n" ); document.write( "divide both sides of the equation by 12 to get:
\n" ); document.write( "64 = b^2.
\n" ); document.write( "take the square root of both sides of the equation to get:
\n" ); document.write( "64 ^ (1/2) = b
\n" ); document.write( "solve for b to get:
\n" ); document.write( "b = 8.
\n" ); document.write( "the equation becomes y = 12 * 8 ^ x.
\n" ); document.write( "that should be it.
\n" ); document.write( "this equation can be graphed as shown below:\r
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\n" ); document.write( "\n" ); document.write( "you can see that, when x = 0, y = 12, and when x = 2, y = 768.
\n" ); document.write( "the formula is good for all values of x.
\n" ); document.write( "x can be negative or positive.
\n" ); document.write( "when x = -1, the formua becomes y = 12 * 8 ^ -1 = 1.5.
\n" ); document.write( "the more negative x becomes, the closer to 0 y gets.
\n" ); document.write( "y will never, however, be equal to 0.
\n" ); document.write( "y = 12 * 8 ^ -30 gets you y = 9.6935 * 10^-27,
\n" ); document.write( "that's a very small positive number, but it is not 0.
\n" ); document.write( "y will never be 0 nor will y ever be negative.\r
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