document.write( "Question 1190049: The perimeter of a rectangular bakery is 174 feet. The area is 1,782 square feet. What are the dimensions of the bakery? \n" ); document.write( "

Algebra.Com's Answer #821608 by ikleyn(52782) $\"\"$ $\"About$

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document.write( "Let x and y be the dimensions.\r\n" );
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document.write( "Then \r\n" );
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document.write( "    x + y = 174/2 = 87      (1)    (half the perimeter)\r\n" );
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document.write( "    xy    = 1782            (2)    (the area)\r\n" );
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document.write( "From first equation, express y = 87-x and substitute into the second equation.\r\n" );
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document.write( "You will get single equation for unknown x\r\n" );
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document.write( "    x*(87-x) = 1782,\r\n" );
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document.write( "or\r\n" );
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document.write( "    x^2 - 87x + 1782 = 0.\r\n" );
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document.write( "Solve it using the quadratic formula.\r\n" );
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document.write( "     =  =  = .\r\n" );
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document.write( "Both roots are good,  x= 54 and x= 33.\r\n" );
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document.write( "First root x= 54 determines y = 87-54 = 33;\r\n" );
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document.write( "second root x= 33 determines y = 87-33 = 54.\r\n" );
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document.write( "So, the dimensions of the bakery are 33 and 54 feet.    ANSWER\r\n" );
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document.write( "CHECK  the area:  33*54 = 1782 square feet.   ! Precisely correct !\r\n" );
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