document.write( "Question 1190015: 1. You manage a bookstore. Your competitor claims that the average textbook at their bookstore costs less than $100. You want to test this claim. You randomly sample 40 books and get the average cost of $95 and the sample standard deviation of this sample to be $20.\r
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document.write( "a. Run the hypothesis test at the standard alpha level of 5% and copy and paste the results below. Make sure you show the Ho, Ha, critical value, test statistic, p-values and decision.\r
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document.write( "b. Summarize your results at the 0.05 alpha level significance level.\r
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Algebra.Com's Answer #821604 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Ho: mu >= 100 \n" ); document.write( "Ha: mu < 100 \n" ); document.write( "This is a left-tailed test because of the inequality sign in the alternative hypothesis. \n" ); document.write( "The rejection region is to the left of the critical value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 40 = sample size \n" ); document.write( "n > 30 so we can use the Z distribution here\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given info: \n" ); document.write( "mu = 100 is what we assume is the case \n" ); document.write( "xbar = sample mean = 95 \n" ); document.write( "s = sample standard deviation = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Test Statistic: \n" ); document.write( "z = (xbar - mu)/(s/sqrt(n)) \n" ); document.write( "z = (95 - 100)/(20/sqrt(40)) \n" ); document.write( "z = -1.58 \n" ); document.write( "The value is approximate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a Z table or calculator to find that \n" ); document.write( "P(Z < -1.58) = 0.05705 \n" ); document.write( "This is the approximate p-value\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The p-value is not less than alpha = 0.05, so we fail to reject the null. \n" ); document.write( "In other words, we don't have enough info to overturn the null. \n" ); document.write( "The null was that mu >= 100, so either mu = 100 or mu > 100. \n" ); document.write( "We can interpret this as \"The average textbook is $100 or more\", or something along those lines.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you were to use a table or calculator, you should find that the z critical value is roughly -1.645 when considering a left-tailed test. \n" ); document.write( "Effectively, \n" ); document.write( "P(Z < -1.645) = 0.05 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Compare the test statistic (-1.58) and the critical value (-1.645) \n" ); document.write( "The test statistic is not to the left of the critical value, so the test statistic is not in the rejection region. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------- \n" ); document.write( "Summary:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Test Statistic: z = -1.58 \n" ); document.write( "critical value: z = -1.645 \n" ); document.write( "P-value = 0.05705 \n" ); document.write( "Decision: Fail to reject the null \n" ); document.write( "Interpretation: The average textbook is $100 or more\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |