document.write( "Question 1190010: Two friends say ‘goodbye’ as they leave the school heading home in different directions. Jayshan
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document.write( "walks 180 metres in one direction and Aneesa runs an unknown number of metres in another direction
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document.write( "such that the angle between the friends is 72°. If the distance between the two friends is 485 metres,
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document.write( "then calculate how far Aneesa ran, rounding your answer to the nearest metre. \n" );
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Algebra.Com's Answer #821603 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x = how far Aneesa ran, in meters \n" ); document.write( " ![]() \n" ); document.write( "Drawing is not to scale\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the law of cosines to solve for x. \n" ); document.write( "c^2 = a^2+b^2 - 2*a*b*cos(C) \n" ); document.write( "485^2 = 180^2+x^2 - 2*180*x*cos(72) \n" ); document.write( "485^2 = 180^2+x^2 - 2*180*x*0.30901699437494 \n" ); document.write( "235225 = 32400+x^2 - 111.246117974979x \n" ); document.write( "0 = 32400+x^2 - 111.246117974979x - 235225 \n" ); document.write( "x^2 - 111.246117974979x - 202825 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From here, you'll need the quadratic formula. I'll skip those steps but you should get the following roots: \n" ); document.write( "x = -398.16 \n" ); document.write( "x = 509.41 \n" ); document.write( "both of which are approximate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We ignore the negative root. It doesn't make sense to have Aneesa run a negative distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only practical solution here is roughly x = 509.41 \n" ); document.write( "This rounds to 509\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 509 meters \n" ); document.write( " \n" ); document.write( " |