document.write( "Question 112713: Geometry. The length of a rectangle is 2 in. more than twice its width. If the
\n" ); document.write( "perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
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Algebra.Com's Answer #82158 by SHUgrad05(58)\"\" \"About 
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Let w=width and l=length.
\n" ); document.write( "Perimeter of a rectangle is P=w+w+l+l
\n" ); document.write( "length=2w+2
\n" ); document.write( "P=w+w+2w+2+2w+2=34
\n" ); document.write( "6w+4=34
\n" ); document.write( "6w=30
\n" ); document.write( "w=5
\n" ); document.write( "l=2(5)+2=12
\n" ); document.write( "width=5 in
\n" ); document.write( "length=12 in\r
\n" ); document.write( "\n" ); document.write( "Check: Perimeter=2w+2l
\n" ); document.write( "10+24=34 in
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