document.write( "Question 1190011: Dilan, a high school student, provides lawn-cutting services during his summer vacation. In the past,
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document.write( "he has averaged 25 clients a week, charging $8 per lawn. After conducting a neighborhood survey,
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document.write( "Dilan realizes that for every $2 increase in price for lawn-cutting, he expects to lose 2 clients.
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document.write( "Determine how much he should charge per lawn to maximize his revenue. \n" );
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Algebra.Com's Answer #821566 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 2x= 2 clients and $2 \n" ); document.write( "x=1 fewer client and $1 more dollar per lawn. \n" ); document.write( "currently 25 clients*$8/client or $200. \n" ); document.write( "(25-x)($8+x)=200+17x-x^2 \n" ); document.write( "This is maximum at the vertex of -b/2a=-17/-2 or 8.5 \n" ); document.write( "has 25-8.50 or 16.5 customers \n" ); document.write( "charges $16.50 per lawn \n" ); document.write( "$276.38 \n" ); document.write( "has to be 16 or 17 customers. \n" ); document.write( "16 would charge $17 for $272 \n" ); document.write( "17 would charge $16 for the same, $272 \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "can check \n" ); document.write( "23 clients with $10 ($230) \n" ); document.write( "21 with with $12 ($252) \n" ); document.write( "19 with $14 ($266) \n" ); document.write( "17 with $16 ($272) \n" ); document.write( "15 with $18 (270) \n" ); document.write( "13 with $20 (260) \n" ); document.write( " \n" ); document.write( " |