document.write( "Question 1189998: The current i (in amperes) at time t in a particular circuit is given by
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Algebra.Com's Answer #821532 by ikleyn(52817)\"\" \"About 
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\n" ); document.write( "The current i (in amperes) at time t in a particular circuit is given by
\n" ); document.write( "i =12sin t + 5cost.
\n" ); document.write( "Find the maximum current and the first time that it occurs.
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document.write( "Doing it in the Calculus frame, take the derivative  \"%28di%29%2F%28dt%29\";  equate it to zero and find the time\r\n" );
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document.write( "The derivative is  \"%28di%29%2F%28dt%29\" = 12cos(t) - 5sin(t).\r\n" );
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document.write( "The equation  \"%28di%29%2F%28dt%29\" = 0  is  12cos(t) - 5sin(t) = 0,  or  12cos(t) = 5sin(t),  which gives\r\n" );
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document.write( "    \"sin%28t%29%2Fcos%28t%29\" = \"12%2F5\",  or  tan(t) = \"12%2F5\",\r\n" );
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document.write( "Hence,  t = arctan(12/5) = 1.176 units of time.   It is the first occurrence time of the maximum.     ANSWER\r\n" );
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document.write( "           Since everything happens in the 1st quadrant, \r\n" );
document.write( "       where both sin(t) and cos(t) are positive, it is clear\r\n" );
document.write( "          that the found extremum is indeed the maximum\r\n" );
document.write( "       (not a minimum), and a special check is not needed.\r\n" );
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document.write( "Next, from tan(t) = \"12%2F5\",  we have  sin(t) = \"12%2Fsqrt%2812%5E2%2B5%5E2%29\" = \"12%2F13\";\r\n" );
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document.write( "                                   cos(t) = \"5%2F13\".\r\n" );
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document.write( "Substituting these values for sin(t) and cos(t) into the formula for \"i\", we obtain the value of  \"i%5Bmax%5D\"\r\n" );
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document.write( "    \"i%5Bmax%5D\" = \"12%2A%2812%2F13%29\" + \"5%2A%285%2F13%29\" = \"%28144%2B25%29%2F13\" = \"169%2F13\" = 13 amperes.    ANSWER.\r\n" );
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