document.write( "Question 112514: A lidless box is constructed from a square peice of tin by cutting a 10cm square from each corner and bending up the sides for the box. If the volume of the box is 1200cm cubed, find the dimensions to the nearest tenth of a centimetre. \n" ); document.write( "

Algebra.Com's Answer #82153 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A lidless box is constructed from a square piece of tin by cutting a 10cm
\n" ); document.write( "square from each corner and bending up the sides for the box. If the volume of
\n" ); document.write( " the box is 1200cm cubed, find the dimensions to the nearest tenth of a centimetre.
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\n" ); document.write( "Let x = length of the sides of the base
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\n" ); document.write( "If you draw a rough diagram, showing the 10cm squares on the corners it will be
\n" ); document.write( " apparent that the height of the box will be 10 cm:
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\n" ); document.write( "We know the Area of the base = $\"volume%2Fheight\"$
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\n" ); document.write( "Base area = $\"1200%2F10\"$ = 120 sq cm
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\n" ); document.write( "x = $\"sqrt%28120%29\"$
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\n" ); document.write( "x = 2* $\"sqrt%2830%29\"$ or 10.95445 cm
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\n" ); document.write( "The dimensions to the nearest tenth: 11 by 11 by 10
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\n" ); document.write( "Check solution: $\"sqrt%28120%29\"$ * $\"sqrt%28120%29\"$ * 10 = 1200
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