document.write( "Question 1189983: A driver travels 115 km on his first day. On his second day he travels 85 km. If this driver has traveled 80% of the distance, how many kilometers does he have left to travel?
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Algebra.Com's Answer #821508 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "x = total distance to travel, in km\r
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\n" ); document.write( "\n" ); document.write( "The driver has done 115+85 = 200 km so far which is 80% of the way there.\r
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\n" ); document.write( "\n" ); document.write( "\"part%2Fwhole+=+percent%2F100\"\r
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\n" ); document.write( "\n" ); document.write( "\"200%2Fx+=+80%2F100\"\r
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\n" ); document.write( "\n" ); document.write( "\"200%2A100+=+80x\"\r
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\n" ); document.write( "\n" ); document.write( "\"20000+=+80x\"\r
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\n" ); document.write( "\n" ); document.write( "\"80x+=+20000\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+20000%2F80\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+250\"\r
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\n" ); document.write( "\n" ); document.write( "Or as a slight alternative, we're solving the equation \"0.80x+=+200\" to get \"x+=+250\"\r
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\n" ); document.write( "\n" ); document.write( "The total distance s/he needs to travel is 250 km.\r
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\n" ); document.write( "\n" ); document.write( "If the driver has done 200 km so far, then there's 250-200 = 50 km left to go.\r
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\n" ); document.write( "\n" ); document.write( "Answer: c) 50
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