document.write( "Question 1189966: The force of attraction, F of a body varies directly as its mass m and inversely as the square of the distance d from the body. When m = 8 kilograms and d = 5 meters, F = 100 Newtons. Find F when = 2 kilograms and d = 15 meters
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document.write( "please show your solution. \n" );
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Algebra.Com's Answer #821491 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The mass is 1/4 as much; since the force of attraction varies directly as the mass, it goes down by a factor of 1/4. \n" ); document.write( "The distance is 3 times as great; since the force varies inversely as the square of the distance, it goes down by a factor of 1/3^2 = 1/9. \n" ); document.write( "ANSWER: (100)(1/4)(1/9) = 100/36 = 25/9 Newtons \n" ); document.write( "Formally.... \n" ); document.write( "(1) Find the constant of variation using the known data \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(2) Use the constant with the new data \n" ); document.write( " \n" ); document.write( "ANSWER (the same, of course): 25/9 Newtons \n" ); document.write( " \n" ); document.write( " |