document.write( "Question 1184165: Jerome wanted to decorate a room by hanging rows of wooden beads across the
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document.write( "windows. He strung 1/3 of the beads in 7 long pieces of string and 4/9 of the beads in
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document.write( "16 short pieces of string. He kept the rest of the beads in a container. Each long piece
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document.write( "of string had 15 more beads than each short piece of string.
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document.write( "(a) What fraction of the beads was kept in the container?
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document.write( "(b) How many beads did Jerome use to create his decoration? \n" );
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Algebra.Com's Answer #821448 by greenestamps(13209) You can put this solution on YOUR website! \n" ); document.write( "(a) The fraction left in the container is \n" ); document.write( " \n" ); document.write( "(b) \n" ); document.write( "1/3 of the beads were used in 7 long strings, so each long string had (1/3)/7 = 1/21 of the total number of beads. \n" ); document.write( "4/9 of the beads were used in 16 short strings, so each short string had (4/9)/16 = 1/36 of the beads. \n" ); document.write( "The number of beads in each long string was 15 more than the number in each short string: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(multiply by the LCM of 36 and 21, which is 21*12=252) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: The total number of beads was 756 \n" ); document.write( "CHECK: \n" ); document.write( "1/3 of 756 is 252; 7 strings of 252/7=36 beads each \n" ); document.write( "4/9 of 756 is 336; 16 strings of 336/16=21 beads each \n" ); document.write( "36-21=15 \n" ); document.write( " \n" ); document.write( " |