document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112452>Question 112452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the circumference of a circle is 3 meters than what is the diamiter and what is the radius? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82144 by </B><A HREF=/tutors/aboutme.mpl?userid=SHUgrad05><B>SHUgrad05(58)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=SHUgrad05><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The circumference of a circle is : C=Pi*d; where d=the diameter\r<BR>\n" );
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document.write( "3=3.14*d -> To find d, divide both sides by 3.14\r<BR>\n" );
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document.write( "0.96=d\r<BR>\n" );
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document.write( "Next we want to find the radius:\r<BR>\n" );
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document.write( "d=2*r\r<BR>\n" );
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document.write( ".96=2*r -> To find r, divide both sides by 2\r<BR>\n" );
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document.write( ".48=r\r<BR>\n" );
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document.write( "Since 3.14 is an appromiximation of Pi, d is approximately equal to 0.96 and r is approximately equal to 0.48 </SPAN>\n" );
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