document.write( "Question 1189920: A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 85% pure antifreeze. The company wants to obtain 255 gallons of a mixture that contains 30% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed? \n" ); document.write( "
Algebra.Com's Answer #821431 by Theo(13342)\"\" \"About 
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x = number of gallons of premium antifreeze solution.
\n" ); document.write( "y = number of gallons of water.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 255
\n" ); document.write( ".85 * x + 0 * y = .3 * 255
\n" ); document.write( "multiply both sides of the first equation by .85 and simplify the second equation to get:
\n" ); document.write( ".85 * x + .85 * y = 216.75
\n" ); document.write( ".85 * x = 0 * y = 76.5
\n" ); document.write( "subtract the second equation from the first to get:
\n" ); document.write( ".85 * y = 140.25
\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 140.25 / .85 = 165
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 255 - 165 = 90
\n" ); document.write( "x + y = 90 + 165 = 255.
\n" ); document.write( "this confirms total gallons at 255.
\n" ); document.write( ".85 * x + 0 * y = .85 * 90 = 0 * 165 = 76.5 / 255 = .3 = 30% antifreeze.
\n" ); document.write( "this confirms total antifreeze solution in the inexpensive mixture = 30%.
\n" ); document.write( "your solution is:
\n" ); document.write( "90 gallons of premium antifreeze and 165 gallons of water must be mixed to get a solution that is 30% antifreeze.\r
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